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swat [-s smb config file] [-a] swat allows a Samba administrator to configure the complex smb.conf file via a Web browser. In addition, a SWAT configuration page has help links to all the configurable options in the smb.conf file making it easy for an administrator to look up the effects of any change. will trace and display contents of SMB packets; it is similar to standard tcpdump utility.

x 0 1 1+ 2 4 f[x] 2 5 1 50

Show that if x cos , y sin , the equations @u @v @u @v ; @x @y @y @x becomes @u 1 @v @v 1 @u ; @ @ @ @

Max[{f[c1], f[c2], f[c3], f[c4]}] //Expand 50 Min[{f[c1], f[c2], f[c3], f[c4]}] //Expand 1 The absolute maximum of f is 50 and the absolute minimum is 1.

EXAMPLE 16 A wire, 100 in. long, is to be used to form a square and a circle. Determine how the wire should be distributed in order for the combined area of the two figures to be (a) as large as possible and (b) as small as possible.

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The combined area of the two figures is A( x ) = x 2 + r 2. The circle has a circumference of 2 r, so it follows that 4 x + 2 r = 100 . Since the wire is 100 in. long, 0 x 25. Solve[4 x + 2 o r 100, r]

testparm [-s] [config file name] [hostname hostIP] testparm is a very simple test program to check an smbd configuration file for internal correctness. If this program reports no problems, you can use the configuration file with confidence that smbd will successfully load the configuration file.

Use Problem 6.80 to show that under the transformation x cos , y sin , the equation @2 u @2 u 0 @x2 @y2 becomes @2 u 1 @u 1 @2 u 0 @ 2 @ 2 @ 2

r 2( 25 + x)

Solve[a'[x] 0] 100 x 4+ x1 = 0; x2 = 100 ; 4+ o x3 = 25;

Find critical value(s).

CHAP. 6]

testprns printername [printcapname] testprns is a very simple test program to determine whether a given printer name is valid for use in a service to be provided by smbd.

Compute the values of a(x) at these three points. The values are placed in a table with numerical approximations for comparison.

points = {{x1, a[x1], N[a[x1]]}, {x2, a[x2], N[a[x2]]}, {x3, a[x3], N[a[x3]]}} //Together; TableForm[points, TableAlignments Center, TableSpacing {2, 5}, TableHeadings {None, {"x", "a[x] "N[a[x]]"}}] ",

x 0 100 4+ 25 a [x] 2500 2500 4+ 625 N [a [x]] 795.775 350.062 625.

Find (a) dy=dx and (b) d 2 y=dx2 if x3 y3 3xy 0. Ans. (a) y x2 = y2 x ; b 2xy= y2 x 3 If xu2 v y3 , 2yu xv3 4x, nd (a) @u ; @x b @v . @y Ans: a v3 3xu2 v2 4 ; 6x2 uv2 2y b 2xu2 3y3 3x2 uv2 y

The largest combined area occurs when x = 0 (all the wire is used to form the circle). The smallest area occurs when one side of the square is 100 (cut the wire 400 from one end). To further confirm that x = 100 gives a 4+ 4+ 4+ minimum area, we can apply the second derivative test. Sign a'' 100 4+ 1 Since the sign of the second derivative at the critical number is positive, A(x) has a relative minimum at 100 . 4+ Since this is the only relative extreme value, it must be the location of the absolute minimum.

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